Three girls, Julie, Raeann and Zara had a total of 1080 coins. Some exchanges were made. First, Julie gave Raeann as many coins as Raeann had. After that, Raeann gave
13 of whatever she had then to Zara. Finally, Zara gave
15 of whatever she had to Julie. As a result, they each had the same number of coins. How many coins did Julie have at first?
|
Julie |
Raeann |
Zara |
Total |
Before 1 |
? |
1 u |
|
1080 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
3 p |
|
1080 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
2 p |
|
|
Before 3 |
|
|
5 boxes |
1080 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
4 boxes |
|
After 3 |
1 group |
1 group |
1 group |
1080 |
3 groups = 1080
1 group = 1080 ÷ 3 = 360
1 group = 4 boxes 4 boxes = 360
1 box = 360 ÷ 4 = 90
2 p = 1 group
1 p = 360 ÷ 2 = 180
3 p = 3 x 180 = 540
3 p = 2 u
2 u = 540
1 u = 540 ÷ 2 = 270
Number of coins that Julie had at first
= 1 group - 1 box + 1 u
= 360 - 90 + 270
= 540
Answer(s): 540