Three girls, Diana, Roshel and Wendy had a total of 4140 stamps. Some exchanges were made. First, Diana gave Roshel as many stamps as Roshel had. After that, Roshel gave
14 of whatever she had then to Wendy. Finally, Wendy gave
15 of whatever she had to Diana. As a result, they each had the same number of stamps. How many stamps did Diana have at first?
|
Diana |
Roshel |
Wendy |
Total |
Before 1 |
? |
1 u |
|
4140 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
4 p |
|
4140 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
3 p |
|
|
Before 3 |
|
|
5 boxes |
4140 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
4 boxes |
|
After 3 |
1 group |
1 group |
1 group |
4140 |
3 groups = 4140
1 group = 4140 ÷ 3 = 1380
1 group = 4 boxes 4 boxes = 1380
1 box = 1380 ÷ 4 = 345
3 p = 1 group
1 p = 1380 ÷ 3 = 460
4 p = 4 x 460 = 1840
4 p = 2 u
2 u = 1840
1 u = 1840 ÷ 2 = 920
Number of stamps that Diana had at first
= 1 group - 1 box + 1 u
= 1380 - 345 + 920
= 1955
Answer(s): 1955