Three girls, Hilda, Shannon and Lucy had a total of 4680 coins. Some exchanges were made. First, Hilda gave Shannon as many coins as Shannon had. After that, Shannon gave
15 of whatever she had then to Lucy. Finally, Lucy gave
14 of whatever she had to Hilda. As a result, they each had the same number of coins. How many coins did Hilda have at first?
|
Hilda |
Shannon |
Lucy |
Total |
Before 1 |
? |
1 u |
|
4680 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
5 p |
|
4680 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
4 p |
|
|
Before 3 |
|
|
4 boxes |
4680 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
3 boxes |
|
After 3 |
1 group |
1 group |
1 group |
4680 |
3 groups = 4680
1 group = 4680 ÷ 3 = 1560
1 group = 3 boxes 3 boxes = 1560
1 box = 1560 ÷ 3 = 520
4 p = 1 group
1 p = 1560 ÷ 4 = 390
5 p = 5 x 390 = 1950
5 p = 2 u
2 u = 1950
1 u = 1950 ÷ 2 = 975
Number of coins that Hilda had at first
= 1 group - 1 box + 1 u
= 1560 - 520 + 975
= 2015
Answer(s): 2015