Three girls, Kimberly, Jen and Xandra had a total of 5400 beads. Some exchanges were made. First, Kimberly gave Jen as many beads as Jen had. After that, Jen gave
15 of whatever she had then to Xandra. Finally, Xandra gave
13 of whatever she had to Kimberly. As a result, they each had the same number of beads. How many beads did Kimberly have at first?
|
Kimberly |
Jen |
Xandra |
Total |
Before 1 |
? |
1 u |
|
5400 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
5 p |
|
5400 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
4 p |
|
|
Before 3 |
|
|
3 boxes |
5400 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
2 boxes |
|
After 3 |
1 group |
1 group |
1 group |
5400 |
3 groups = 5400
1 group = 5400 ÷ 3 = 1800
1 group = 2 boxes 2 boxes = 1800
1 box = 1800 ÷ 2 = 900
4 p = 1 group
1 p = 1800 ÷ 4 = 450
5 p = 5 x 450 = 2250
5 p = 2 u
2 u = 2250
1 u = 2250 ÷ 2 = 1125
Number of beads that Kimberly had at first
= 1 group - 1 box + 1 u
= 1800 - 900 + 1125
= 2025
Answer(s): 2025