Three girls, Shannon, Opal and Marion had a total of 2610 buttons. Some exchanges were made. First, Shannon gave Opal as many buttons as Opal had. After that, Opal gave
14 of whatever she had then to Marion. Finally, Marion gave
14 of whatever she had to Shannon. As a result, they each had the same number of buttons. How many buttons did Shannon have at first?
|
Shannon |
Opal |
Marion |
Total |
Before 1 |
? |
1 u |
|
2610 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
4 p |
|
2610 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
3 p |
|
|
Before 3 |
|
|
4 boxes |
2610 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
3 boxes |
|
After 3 |
1 group |
1 group |
1 group |
2610 |
3 groups = 2610
1 group = 2610 ÷ 3 = 870
1 group = 3 boxes 3 boxes = 870
1 box = 870 ÷ 3 = 290
3 p = 1 group
1 p = 870 ÷ 3 = 290
4 p = 4 x 290 = 1160
4 p = 2 u
2 u = 1160
1 u = 1160 ÷ 2 = 580
Number of buttons that Shannon had at first
= 1 group - 1 box + 1 u
= 870 - 290 + 580
= 1160
Answer(s): 1160