Three girls, Yen, Linda and Jade had a total of 840 coins. Some exchanges were made. First, Yen gave Linda as many coins as Linda had. After that, Linda gave
13 of whatever she had then to Jade. Finally, Jade gave
13 of whatever she had to Yen. As a result, they each had the same number of coins. How many coins did Yen have at first?
|
Yen |
Linda |
Jade |
Total |
Before 1 |
? |
1 u |
|
840 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
3 p |
|
840 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
2 p |
|
|
Before 3 |
|
|
3 boxes |
840 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
2 boxes |
|
After 3 |
1 group |
1 group |
1 group |
840 |
3 groups = 840
1 group = 840 ÷ 3 = 280
1 group = 2 boxes 2 boxes = 280
1 box = 280 ÷ 2 = 140
2 p = 1 group
1 p = 280 ÷ 2 = 140
3 p = 3 x 140 = 420
3 p = 2 u
2 u = 420
1 u = 420 ÷ 2 = 210
Number of coins that Yen had at first
= 1 group - 1 box + 1 u
= 280 - 140 + 210
= 350
Answer(s): 350