Three girls, Jade, Elyse and Pamela had a total of 1890 pens. Some exchanges were made. First, Jade gave Elyse as many pens as Elyse had. After that, Elyse gave
14 of whatever she had then to Pamela. Finally, Pamela gave
13 of whatever she had to Jade. As a result, they each had the same number of pens. How many pens did Jade have at first?
|
Jade |
Elyse |
Pamela |
Total |
Before 1 |
? |
1 u |
|
1890 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
4 p |
|
1890 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
3 p |
|
|
Before 3 |
|
|
3 boxes |
1890 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
2 boxes |
|
After 3 |
1 group |
1 group |
1 group |
1890 |
3 groups = 1890
1 group = 1890 ÷ 3 = 630
1 group = 2 boxes 2 boxes = 630
1 box = 630 ÷ 2 = 315
3 p = 1 group
1 p = 630 ÷ 3 = 210
4 p = 4 x 210 = 840
4 p = 2 u
2 u = 840
1 u = 840 ÷ 2 = 420
Number of pens that Jade had at first
= 1 group - 1 box + 1 u
= 630 - 315 + 420
= 735
Answer(s): 735