Victoria, Yoko and Xuan have 225 erasers. Victoria has
23 as many erasers as Yoko. Xuan's erasers is
14 of the total number of Victoria's and Yoko's erasers. How many erasers must Yoko give to Xuan so that both Victoria and Xuan will have the same number of erasers?
Victoria |
Yoko |
Xuan |
Total |
4x5 = 20 u |
1x5 = 5 u |
|
2x4 = 8 u |
3x4 = 12 u |
|
|
8 u |
12 u |
5 u |
225 |
Total number of erasers
= 8 u + 12 u + 5 u
= 25 u
25 u = 225
1 u = 225 ÷ 25 = 9
Victoria |
Yoko |
Xuan |
Total |
8 u |
12 u |
5 u |
225 |
|
- 3 u |
+ 3 u |
|
8 u |
9 u |
8 u |
225 |
Number of erasers that Yoko must give to Xuan
= 8 u - 5 u
= 3 u
= 3 x 9
= 27
Answer(s): 27