Rachel, Cathy and Xylia have 432 buttons. Rachel has
45 as many buttons as Cathy. Xylia's buttons is
15 of the total number of Rachel's and Cathy's buttons. How many buttons must Cathy give to Xylia so that both Rachel and Xylia will have the same number of buttons?
Rachel |
Cathy |
Xylia |
Total |
5x9 = 45 u |
1x9 = 9 u |
|
4x5 = 20 u |
5x5 = 25 u |
|
|
20 u |
25 u |
9 u |
432 |
Total number of buttons
= 20 u + 25 u + 9 u
= 54 u
54 u = 432
1 u = 432 ÷ 54 = 8
Rachel |
Cathy |
Xylia |
Total |
20 u |
25 u |
9 u |
432 |
|
- 11 u |
+ 11 u |
|
20 u |
14 u |
20 u |
432 |
Number of buttons that Cathy must give to Xylia
= 20 u - 9 u
= 11 u
= 11 x 8
= 88
Answer(s): 88