Cindy, Sabrina and Lynn have 210 marbles. Cindy has
34 as many marbles as Sabrina. Lynn's marbles is
15 of the total number of Cindy's and Sabrina's marbles. How many marbles must Sabrina give to Lynn so that both Cindy and Lynn will have the same number of marbles?
| Cindy |
Sabrina |
Lynn |
Total |
5x7 =
35 u |
1x7 =
7 u |
|
3x5 =
15 u |
4x5 =
20 u |
|
|
| 15 u |
20 u |
7 u |
210 |
Total number of marbles
= 15 u + 20 u + 7 u
= 42 u
42 u = 210
1 u = 210 ÷ 42 = 5
| Cindy |
Sabrina |
Lynn |
Total |
| 15 u |
20 u |
7 u |
210 |
| |
- 8 u |
+ 8 u |
|
| 15 u |
12 u |
15 u |
210 |
Number of marbles that Sabrina must give to Lynn
= 15 u - 7 u
= 8 u
= 8 x 5
= 40
Answer(s): 40
