Kylie, Dana and Kathy have 88 stickers. Kylie has
56 as many stickers as Dana. Kathy's stickers is
13 of the total number of Kylie's and Dana's stickers. How many stickers must Dana give to Kathy so that both Kylie and Kathy will have the same number of stickers?
| Kylie |
Dana |
Kathy |
Total |
3x11 =
33 u |
1x11 =
11 u |
|
5x3 =
15 u |
6x3 =
18 u |
|
|
| 15 u |
18 u |
11 u |
88 |
Total number of stickers
= 15 u + 18 u + 11 u
= 44 u
44 u = 88
1 u = 88 ÷ 44 = 2
| Kylie |
Dana |
Kathy |
Total |
| 15 u |
18 u |
11 u |
88 |
| |
- 4 u |
+ 4 u |
|
| 15 u |
14 u |
15 u |
88 |
Number of stickers that Dana must give to Kathy
= 15 u - 11 u
= 4 u
= 4 x 2
= 8
Answer(s): 8
