Julie, Shannon and Betty have 88 cards. Julie has
56 as many cards as Shannon. Betty's cards is
13 of the total number of Julie's and Shannon's cards. How many cards must Shannon give to Betty so that both Julie and Betty will have the same number of cards?
| Julie |
Shannon |
Betty |
Total |
3x11 =
33 u |
1x11 =
11 u |
|
5x3 =
15 u |
6x3 =
18 u |
|
|
| 15 u |
18 u |
11 u |
88 |
Total number of cards
= 15 u + 18 u + 11 u
= 44 u
44 u = 88
1 u = 88 ÷ 44 = 2
| Julie |
Shannon |
Betty |
Total |
| 15 u |
18 u |
11 u |
88 |
| |
- 4 u |
+ 4 u |
|
| 15 u |
14 u |
15 u |
88 |
Number of cards that Shannon must give to Betty
= 15 u - 11 u
= 4 u
= 4 x 2
= 8
Answer(s): 8
