Usha, Raeann and Mary have 352 erasers. Usha has
56 as many erasers as Raeann. Mary's erasers is
13 of the total number of Usha's and Raeann's erasers. How many erasers must Raeann give to Mary so that both Usha and Mary will have the same number of erasers?
| Usha |
Raeann |
Mary |
Total |
3x11 =
33 u |
1x11 =
11 u |
|
5x3 =
15 u |
6x3 =
18 u |
|
|
| 15 u |
18 u |
11 u |
352 |
Total number of erasers
= 15 u + 18 u + 11 u
= 44 u
44 u = 352
1 u = 352 ÷ 44 = 8
| Usha |
Raeann |
Mary |
Total |
| 15 u |
18 u |
11 u |
352 |
| |
- 4 u |
+ 4 u |
|
| 15 u |
14 u |
15 u |
352 |
Number of erasers that Raeann must give to Mary
= 15 u - 11 u
= 4 u
= 4 x 8
= 32
Answer(s): 32
