Diana, Xylia and Yoko have 175 pens. Diana has
23 as many pens as Xylia. Yoko's pens is
14 of the total number of Diana's and Xylia's pens. How many pens must Xylia give to Yoko so that both Diana and Yoko will have the same number of pens?
Diana |
Xylia |
Yoko |
Total |
4x5 = 20 u |
1x5 = 5 u |
|
2x4 = 8 u |
3x4 = 12 u |
|
|
8 u |
12 u |
5 u |
175 |
Total number of pens
= 8 u + 12 u + 5 u
= 25 u
25 u = 175
1 u = 175 ÷ 25 = 7
Diana |
Xylia |
Yoko |
Total |
8 u |
12 u |
5 u |
175 |
|
- 3 u |
+ 3 u |
|
8 u |
9 u |
8 u |
175 |
Number of pens that Xylia must give to Yoko
= 8 u - 5 u
= 3 u
= 3 x 7
= 21
Answer(s): 21