Jaslyn, Tammy and Penelope have 288 stickers. Jaslyn has
35 as many stickers as Tammy. Penelope's stickers is
15 of the total number of Jaslyn's and Tammy's stickers. How many stickers must Tammy give to Penelope so that both Jaslyn and Penelope will have the same number of stickers?
Jaslyn |
Tammy |
Penelope |
Total |
5x8 = 40 u |
1x8 = 8 u |
|
3x5 = 15 u |
5x5 = 25 u |
|
|
15 u |
25 u |
8 u |
288 |
Total number of stickers
= 15 u + 25 u + 8 u
= 48 u
48 u = 288
1 u = 288 ÷ 48 = 6
Jaslyn |
Tammy |
Penelope |
Total |
15 u |
25 u |
8 u |
288 |
|
- 7 u |
+ 7 u |
|
15 u |
18 u |
15 u |
288 |
Number of stickers that Tammy must give to Penelope
= 15 u - 8 u
= 7 u
= 7 x 6
= 42
Answer(s): 42