Betty, Elyse and Raeann have 168 erasers. Betty has
34 as many erasers as Elyse. Raeann's erasers is
13 of the total number of Betty's and Elyse's erasers. How many erasers must Elyse give to Raeann so that both Betty and Raeann will have the same number of erasers?
Betty |
Elyse |
Raeann |
Total |
3x7 = 21 u |
1x7 = 7 u |
|
3x3 = 9 u |
4x3 = 12 u |
|
|
9 u |
12 u |
7 u |
168 |
Total number of erasers
= 9 u + 12 u + 7 u
= 28 u
28 u = 168
1 u = 168 ÷ 28 = 6
Betty |
Elyse |
Raeann |
Total |
9 u |
12 u |
7 u |
168 |
|
- 2 u |
+ 2 u |
|
9 u |
10 u |
9 u |
168 |
Number of erasers that Elyse must give to Raeann
= 9 u - 7 u
= 2 u
= 2 x 6
= 12
Answer(s): 12