Rachel, Natalie and Dana have 132 pens. Rachel has
56 as many pens as Natalie. Dana's pens is
13 of the total number of Rachel's and Natalie's pens. How many pens must Natalie give to Dana so that both Rachel and Dana will have the same number of pens?
Rachel |
Natalie |
Dana |
Total |
3x11 = 33 u |
1x11 = 11 u |
|
5x3 = 15 u |
6x3 = 18 u |
|
|
15 u |
18 u |
11 u |
132 |
Total number of pens
= 15 u + 18 u + 11 u
= 44 u
44 u = 132
1 u = 132 ÷ 44 = 3
Rachel |
Natalie |
Dana |
Total |
15 u |
18 u |
11 u |
132 |
|
- 4 u |
+ 4 u |
|
15 u |
14 u |
15 u |
132 |
Number of pens that Natalie must give to Dana
= 15 u - 11 u
= 4 u
= 4 x 3
= 12
Answer(s): 12