Xylia, Shiyun and Gwen have 264 marbles. Xylia has
56 as many marbles as Shiyun. Gwen's marbles is
15 of the total number of Xylia's and Shiyun's marbles. How many marbles must Shiyun give to Gwen so that both Xylia and Gwen will have the same number of marbles?
Xylia |
Shiyun |
Gwen |
Total |
5x11 = 55 u |
1x11 = 11 u |
|
5x5 = 25 u |
6x5 = 30 u |
|
|
25 u |
30 u |
11 u |
264 |
Total number of marbles
= 25 u + 30 u + 11 u
= 66 u
66 u = 264
1 u = 264 ÷ 66 = 4
Xylia |
Shiyun |
Gwen |
Total |
25 u |
30 u |
11 u |
264 |
|
- 14 u |
+ 14 u |
|
25 u |
16 u |
25 u |
264 |
Number of marbles that Shiyun must give to Gwen
= 25 u - 11 u
= 14 u
= 14 x 4
= 56
Answer(s): 56