Mary, Jen and Kylie have 550 pens. Mary has
56 as many pens as Jen. Kylie's pens is
14 of the total number of Mary's and Jen's pens. How many pens must Jen give to Kylie so that both Mary and Kylie will have the same number of pens?
Mary |
Jen |
Kylie |
Total |
4x11 = 44 u |
1x11 = 11 u |
|
5x4 = 20 u |
6x4 = 24 u |
|
|
20 u |
24 u |
11 u |
550 |
Total number of pens
= 20 u + 24 u + 11 u
= 55 u
55 u = 550
1 u = 550 ÷ 55 = 10
Mary |
Jen |
Kylie |
Total |
20 u |
24 u |
11 u |
550 |
|
- 9 u |
+ 9 u |
|
20 u |
15 u |
20 u |
550 |
Number of pens that Jen must give to Kylie
= 20 u - 11 u
= 9 u
= 9 x 10
= 90
Answer(s): 90