Tammy, Diana and Cathy have 504 cards. Tammy has
34 as many cards as Diana. Cathy's cards is
15 of the total number of Tammy's and Diana's cards. How many cards must Diana give to Cathy so that both Tammy and Cathy will have the same number of cards?
Tammy |
Diana |
Cathy |
Total |
5x7 = 35 u |
1x7 = 7 u |
|
3x5 = 15 u |
4x5 = 20 u |
|
|
15 u |
20 u |
7 u |
504 |
Total number of cards
= 15 u + 20 u + 7 u
= 42 u
42 u = 504
1 u = 504 ÷ 42 = 12
Tammy |
Diana |
Cathy |
Total |
15 u |
20 u |
7 u |
504 |
|
- 8 u |
+ 8 u |
|
15 u |
12 u |
15 u |
504 |
Number of cards that Diana must give to Cathy
= 15 u - 7 u
= 8 u
= 8 x 12
= 96
Answer(s): 96