Hilda, Lucy and Opal have 540 pens. Hilda has
45 as many pens as Lucy. Opal's pens is
15 of the total number of Hilda's and Lucy's pens. How many pens must Lucy give to Opal so that both Hilda and Opal will have the same number of pens?
Hilda |
Lucy |
Opal |
Total |
5x9 = 45 u |
1x9 = 9 u |
|
4x5 = 20 u |
5x5 = 25 u |
|
|
20 u |
25 u |
9 u |
540 |
Total number of pens
= 20 u + 25 u + 9 u
= 54 u
54 u = 540
1 u = 540 ÷ 54 = 10
Hilda |
Lucy |
Opal |
Total |
20 u |
25 u |
9 u |
540 |
|
- 11 u |
+ 11 u |
|
20 u |
14 u |
20 u |
540 |
Number of pens that Lucy must give to Opal
= 20 u - 9 u
= 11 u
= 11 x 10
= 110
Answer(s): 110