Linda, Shannon and Tiffany have 462 cards. Linda has
56 as many cards as Shannon. Tiffany's cards is
15 of the total number of Linda's and Shannon's cards. How many cards must Shannon give to Tiffany so that both Linda and Tiffany will have the same number of cards?
Linda |
Shannon |
Tiffany |
Total |
5x11 = 55 u |
1x11 = 11 u |
|
5x5 = 25 u |
6x5 = 30 u |
|
|
25 u |
30 u |
11 u |
462 |
Total number of cards
= 25 u + 30 u + 11 u
= 66 u
66 u = 462
1 u = 462 ÷ 66 = 7
Linda |
Shannon |
Tiffany |
Total |
25 u |
30 u |
11 u |
462 |
|
- 14 u |
+ 14 u |
|
25 u |
16 u |
25 u |
462 |
Number of cards that Shannon must give to Tiffany
= 25 u - 11 u
= 14 u
= 14 x 7
= 98
Answer(s): 98