Penelope, Tina and Kylie have 198 pens. Penelope has
56 as many pens as Tina. Kylie's pens is
15 of the total number of Penelope's and Tina's pens. How many pens must Tina give to Kylie so that both Penelope and Kylie will have the same number of pens?
Penelope |
Tina |
Kylie |
Total |
5x11 = 55 u |
1x11 = 11 u |
|
5x5 = 25 u |
6x5 = 30 u |
|
|
25 u |
30 u |
11 u |
198 |
Total number of pens
= 25 u + 30 u + 11 u
= 66 u
66 u = 198
1 u = 198 ÷ 66 = 3
Penelope |
Tina |
Kylie |
Total |
25 u |
30 u |
11 u |
198 |
|
- 14 u |
+ 14 u |
|
25 u |
16 u |
25 u |
198 |
Number of pens that Tina must give to Kylie
= 25 u - 11 u
= 14 u
= 14 x 3
= 42
Answer(s): 42