Roshel, Dana and Anna have 210 pens. Roshel has
34 as many pens as Dana. Anna's pens is
15 of the total number of Roshel's and Dana's pens. How many pens must Dana give to Anna so that both Roshel and Anna will have the same number of pens?
Roshel |
Dana |
Anna |
Total |
5x7 = 35 u |
1x7 = 7 u |
|
3x5 = 15 u |
4x5 = 20 u |
|
|
15 u |
20 u |
7 u |
210 |
Total number of pens
= 15 u + 20 u + 7 u
= 42 u
42 u = 210
1 u = 210 ÷ 42 = 5
Roshel |
Dana |
Anna |
Total |
15 u |
20 u |
7 u |
210 |
|
- 8 u |
+ 8 u |
|
15 u |
12 u |
15 u |
210 |
Number of pens that Dana must give to Anna
= 15 u - 7 u
= 8 u
= 8 x 5
= 40
Answer(s): 40