Lynn, Xuan and Pamela have 168 buttons. Lynn has
34 as many buttons as Xuan. Pamela's buttons is
15 of the total number of Lynn's and Xuan's buttons. How many buttons must Xuan give to Pamela so that both Lynn and Pamela will have the same number of buttons?
| Lynn |
Xuan |
Pamela |
Total |
5x7 =
35 u |
1x7 =
7 u |
|
3x5 =
15 u |
4x5 =
20 u |
|
|
| 15 u |
20 u |
7 u |
168 |
Total number of buttons
= 15 u + 20 u + 7 u
= 42 u
42 u = 168
1 u = 168 ÷ 42 = 4
| Lynn |
Xuan |
Pamela |
Total |
| 15 u |
20 u |
7 u |
168 |
| |
- 8 u |
+ 8 u |
|
| 15 u |
12 u |
15 u |
168 |
Number of buttons that Xuan must give to Pamela
= 15 u - 7 u
= 8 u
= 8 x 4
= 32
Answer(s): 32
