Cindy, Linda and Sabrina have 192 pens. Cindy has
35 as many pens as Linda. Sabrina's pens is
15 of the total number of Cindy's and Linda's pens. How many pens must Linda give to Sabrina so that both Cindy and Sabrina will have the same number of pens?
Cindy |
Linda |
Sabrina |
Total |
5x8 = 40 u |
1x8 = 8 u |
|
3x5 = 15 u |
5x5 = 25 u |
|
|
15 u |
25 u |
8 u |
192 |
Total number of pens
= 15 u + 25 u + 8 u
= 48 u
48 u = 192
1 u = 192 ÷ 48 = 4
Cindy |
Linda |
Sabrina |
Total |
15 u |
25 u |
8 u |
192 |
|
- 7 u |
+ 7 u |
|
15 u |
18 u |
15 u |
192 |
Number of pens that Linda must give to Sabrina
= 15 u - 8 u
= 7 u
= 7 x 4
= 28
Answer(s): 28