Fanny, Raeann and Jane have 350 buttons. Fanny has
34 as many buttons as Raeann. Jane's buttons is
14 of the total number of Fanny's and Raeann's buttons. How many buttons must Raeann give to Jane so that both Fanny and Jane will have the same number of buttons?
Fanny |
Raeann |
Jane |
Total |
4x7 = 28 u |
1x7 = 7 u |
|
3x4 = 12 u |
4x4 = 16 u |
|
|
12 u |
16 u |
7 u |
350 |
Total number of buttons
= 12 u + 16 u + 7 u
= 35 u
35 u = 350
1 u = 350 ÷ 35 = 10
Fanny |
Raeann |
Jane |
Total |
12 u |
16 u |
7 u |
350 |
|
- 5 u |
+ 5 u |
|
12 u |
11 u |
12 u |
350 |
Number of buttons that Raeann must give to Jane
= 12 u - 7 u
= 5 u
= 5 x 10
= 50
Answer(s): 50