Xylia, Esther and Dana have 220 marbles. Xylia has
56 as many marbles as Esther. Dana's marbles is
14 of the total number of Xylia's and Esther's marbles. How many marbles must Esther give to Dana so that both Xylia and Dana will have the same number of marbles?
Xylia |
Esther |
Dana |
Total |
4x11 = 44 u |
1x11 = 11 u |
|
5x4 = 20 u |
6x4 = 24 u |
|
|
20 u |
24 u |
11 u |
220 |
Total number of marbles
= 20 u + 24 u + 11 u
= 55 u
55 u = 220
1 u = 220 ÷ 55 = 4
Xylia |
Esther |
Dana |
Total |
20 u |
24 u |
11 u |
220 |
|
- 9 u |
+ 9 u |
|
20 u |
15 u |
20 u |
220 |
Number of marbles that Esther must give to Dana
= 20 u - 11 u
= 9 u
= 9 x 4
= 36
Answer(s): 36