Eva, Gabby and Kimberly have 384 cards. Eva has
35 as many cards as Gabby. Kimberly's cards is
15 of the total number of Eva's and Gabby's cards. How many cards must Gabby give to Kimberly so that both Eva and Kimberly will have the same number of cards?
| Eva |
Gabby |
Kimberly |
Total |
5x8 =
40 u |
1x8 =
8 u |
|
3x5 =
15 u |
5x5 =
25 u |
|
|
| 15 u |
25 u |
8 u |
384 |
Total number of cards
= 15 u + 25 u + 8 u
= 48 u
48 u = 384
1 u = 384 ÷ 48 = 8
| Eva |
Gabby |
Kimberly |
Total |
| 15 u |
25 u |
8 u |
384 |
| |
- 7 u |
+ 7 u |
|
| 15 u |
18 u |
15 u |
384 |
Number of cards that Gabby must give to Kimberly
= 15 u - 8 u
= 7 u
= 7 x 8
= 56
Answer(s): 56
