Nicole, Jen and Gabby have 252 coins. Nicole has
34 as many coins as Jen. Gabby's coins is
15 of the total number of Nicole's and Jen's coins. How many coins must Jen give to Gabby so that both Nicole and Gabby will have the same number of coins?
Nicole |
Jen |
Gabby |
Total |
5x7 = 35 u |
1x7 = 7 u |
|
3x5 = 15 u |
4x5 = 20 u |
|
|
15 u |
20 u |
7 u |
252 |
Total number of coins
= 15 u + 20 u + 7 u
= 42 u
42 u = 252
1 u = 252 ÷ 42 = 6
Nicole |
Jen |
Gabby |
Total |
15 u |
20 u |
7 u |
252 |
|
- 8 u |
+ 8 u |
|
15 u |
12 u |
15 u |
252 |
Number of coins that Jen must give to Gabby
= 15 u - 7 u
= 8 u
= 8 x 6
= 48
Answer(s): 48