Mary, Victoria and Kylie have 84 erasers. Mary has
34 as many erasers as Victoria. Kylie's erasers is
13 of the total number of Mary's and Victoria's erasers. How many erasers must Victoria give to Kylie so that both Mary and Kylie will have the same number of erasers?
Mary |
Victoria |
Kylie |
Total |
3x7 = 21 u |
1x7 = 7 u |
|
3x3 = 9 u |
4x3 = 12 u |
|
|
9 u |
12 u |
7 u |
84 |
Total number of erasers
= 9 u + 12 u + 7 u
= 28 u
28 u = 84
1 u = 84 ÷ 28 = 3
Mary |
Victoria |
Kylie |
Total |
9 u |
12 u |
7 u |
84 |
|
- 2 u |
+ 2 u |
|
9 u |
10 u |
9 u |
84 |
Number of erasers that Victoria must give to Kylie
= 9 u - 7 u
= 2 u
= 2 x 3
= 6
Answer(s): 6