Fanny, Tiffany and Roshel have 96 pens. Fanny has
35 as many pens as Tiffany. Roshel's pens is
15 of the total number of Fanny's and Tiffany's pens. How many pens must Tiffany give to Roshel so that both Fanny and Roshel will have the same number of pens?
| Fanny |
Tiffany |
Roshel |
Total |
5x8 =
40 u |
1x8 =
8 u |
|
3x5 =
15 u |
5x5 =
25 u |
|
|
| 15 u |
25 u |
8 u |
96 |
Total number of pens
= 15 u + 25 u + 8 u
= 48 u
48 u = 96
1 u = 96 ÷ 48 = 2
| Fanny |
Tiffany |
Roshel |
Total |
| 15 u |
25 u |
8 u |
96 |
| |
- 7 u |
+ 7 u |
|
| 15 u |
18 u |
15 u |
96 |
Number of pens that Tiffany must give to Roshel
= 15 u - 8 u
= 7 u
= 7 x 2
= 14
Answer(s): 14
