Lynn, Barbara and Sabrina have 396 coins. Lynn has
56 as many coins as Barbara. Sabrina's coins is
13 of the total number of Lynn's and Barbara's coins. How many coins must Barbara give to Sabrina so that both Lynn and Sabrina will have the same number of coins?
Lynn |
Barbara |
Sabrina |
Total |
3x11 = 33 u |
1x11 = 11 u |
|
5x3 = 15 u |
6x3 = 18 u |
|
|
15 u |
18 u |
11 u |
396 |
Total number of coins
= 15 u + 18 u + 11 u
= 44 u
44 u = 396
1 u = 396 ÷ 44 = 9
Lynn |
Barbara |
Sabrina |
Total |
15 u |
18 u |
11 u |
396 |
|
- 4 u |
+ 4 u |
|
15 u |
14 u |
15 u |
396 |
Number of coins that Barbara must give to Sabrina
= 15 u - 11 u
= 4 u
= 4 x 9
= 36
Answer(s): 36