Kathy, Penelope and Lynn have 440 stickers. Kathy has
56 as many stickers as Penelope. Lynn's stickers is
13 of the total number of Kathy's and Penelope's stickers. How many stickers must Penelope give to Lynn so that both Kathy and Lynn will have the same number of stickers?
Kathy |
Penelope |
Lynn |
Total |
3x11 = 33 u |
1x11 = 11 u |
|
5x3 = 15 u |
6x3 = 18 u |
|
|
15 u |
18 u |
11 u |
440 |
Total number of stickers
= 15 u + 18 u + 11 u
= 44 u
44 u = 440
1 u = 440 ÷ 44 = 10
Kathy |
Penelope |
Lynn |
Total |
15 u |
18 u |
11 u |
440 |
|
- 4 u |
+ 4 u |
|
15 u |
14 u |
15 u |
440 |
Number of stickers that Penelope must give to Lynn
= 15 u - 11 u
= 4 u
= 4 x 10
= 40
Answer(s): 40