Shiyun, Marion and Emily have 132 cards. Shiyun has
56 as many cards as Marion. Emily's cards is
13 of the total number of Shiyun's and Marion's cards. How many cards must Marion give to Emily so that both Shiyun and Emily will have the same number of cards?
Shiyun |
Marion |
Emily |
Total |
3x11 = 33 u |
1x11 = 11 u |
|
5x3 = 15 u |
6x3 = 18 u |
|
|
15 u |
18 u |
11 u |
132 |
Total number of cards
= 15 u + 18 u + 11 u
= 44 u
44 u = 132
1 u = 132 ÷ 44 = 3
Shiyun |
Marion |
Emily |
Total |
15 u |
18 u |
11 u |
132 |
|
- 4 u |
+ 4 u |
|
15 u |
14 u |
15 u |
132 |
Number of cards that Marion must give to Emily
= 15 u - 11 u
= 4 u
= 4 x 3
= 12
Answer(s): 12