Risa, Nora and Winnie have 432 coins. Risa has
35 as many coins as Nora. Winnie's coins is
15 of the total number of Risa's and Nora's coins. How many coins must Nora give to Winnie so that both Risa and Winnie will have the same number of coins?
Risa |
Nora |
Winnie |
Total |
5x8 = 40 u |
1x8 = 8 u |
|
3x5 = 15 u |
5x5 = 25 u |
|
|
15 u |
25 u |
8 u |
432 |
Total number of coins
= 15 u + 25 u + 8 u
= 48 u
48 u = 432
1 u = 432 ÷ 48 = 9
Risa |
Nora |
Winnie |
Total |
15 u |
25 u |
8 u |
432 |
|
- 7 u |
+ 7 u |
|
15 u |
18 u |
15 u |
432 |
Number of coins that Nora must give to Winnie
= 15 u - 8 u
= 7 u
= 7 x 9
= 63
Answer(s): 63