Anna, Elyse and Irene have 110 stickers. Anna has
56 as many stickers as Elyse. Irene's stickers is
14 of the total number of Anna's and Elyse's stickers. How many stickers must Elyse give to Irene so that both Anna and Irene will have the same number of stickers?
Anna |
Elyse |
Irene |
Total |
4x11 = 44 u |
1x11 = 11 u |
|
5x4 = 20 u |
6x4 = 24 u |
|
|
20 u |
24 u |
11 u |
110 |
Total number of stickers
= 20 u + 24 u + 11 u
= 55 u
55 u = 110
1 u = 110 ÷ 55 = 2
Anna |
Elyse |
Irene |
Total |
20 u |
24 u |
11 u |
110 |
|
- 9 u |
+ 9 u |
|
20 u |
15 u |
20 u |
110 |
Number of stickers that Elyse must give to Irene
= 20 u - 11 u
= 9 u
= 9 x 2
= 18
Answer(s): 18