Elyse, Irene and Betty have 270 marbles. Elyse has
45 as many marbles as Irene. Betty's marbles is
14 of the total number of Elyse's and Irene's marbles. How many marbles must Irene give to Betty so that both Elyse and Betty will have the same number of marbles?
Elyse |
Irene |
Betty |
Total |
4x9 = 36 u |
1x9 = 9 u |
|
4x4 = 16 u |
5x4 = 20 u |
|
|
16 u |
20 u |
9 u |
270 |
Total number of marbles
= 16 u + 20 u + 9 u
= 45 u
45 u = 270
1 u = 270 ÷ 45 = 6
Elyse |
Irene |
Betty |
Total |
16 u |
20 u |
9 u |
270 |
|
- 7 u |
+ 7 u |
|
16 u |
13 u |
16 u |
270 |
Number of marbles that Irene must give to Betty
= 16 u - 9 u
= 7 u
= 7 x 6
= 42
Answer(s): 42