Emma, Cindy and Linda have 270 buttons. Emma has
45 as many buttons as Cindy. Linda's buttons is
14 of the total number of Emma's and Cindy's buttons. How many buttons must Cindy give to Linda so that both Emma and Linda will have the same number of buttons?
Emma |
Cindy |
Linda |
Total |
4x9 = 36 u |
1x9 = 9 u |
|
4x4 = 16 u |
5x4 = 20 u |
|
|
16 u |
20 u |
9 u |
270 |
Total number of buttons
= 16 u + 20 u + 9 u
= 45 u
45 u = 270
1 u = 270 ÷ 45 = 6
Emma |
Cindy |
Linda |
Total |
16 u |
20 u |
9 u |
270 |
|
- 7 u |
+ 7 u |
|
16 u |
13 u |
16 u |
270 |
Number of buttons that Cindy must give to Linda
= 16 u - 9 u
= 7 u
= 7 x 6
= 42
Answer(s): 42