Kimberly, Linda and Jaslyn have 252 coins. Kimberly has
34 as many coins as Linda. Jaslyn's coins is
15 of the total number of Kimberly's and Linda's coins. How many coins must Linda give to Jaslyn so that both Kimberly and Jaslyn will have the same number of coins?
Kimberly |
Linda |
Jaslyn |
Total |
5x7 = 35 u |
1x7 = 7 u |
|
3x5 = 15 u |
4x5 = 20 u |
|
|
15 u |
20 u |
7 u |
252 |
Total number of coins
= 15 u + 20 u + 7 u
= 42 u
42 u = 252
1 u = 252 ÷ 42 = 6
Kimberly |
Linda |
Jaslyn |
Total |
15 u |
20 u |
7 u |
252 |
|
- 8 u |
+ 8 u |
|
15 u |
12 u |
15 u |
252 |
Number of coins that Linda must give to Jaslyn
= 15 u - 7 u
= 8 u
= 8 x 6
= 48
Answer(s): 48