Hazel, Hilda and Eva have 528 beads. Hazel has
56 as many beads as Hilda. Eva's beads is
13 of the total number of Hazel's and Hilda's beads. How many beads must Hilda give to Eva so that both Hazel and Eva will have the same number of beads?
Hazel |
Hilda |
Eva |
Total |
3x11 = 33 u |
1x11 = 11 u |
|
5x3 = 15 u |
6x3 = 18 u |
|
|
15 u |
18 u |
11 u |
528 |
Total number of beads
= 15 u + 18 u + 11 u
= 44 u
44 u = 528
1 u = 528 ÷ 44 = 12
Hazel |
Hilda |
Eva |
Total |
15 u |
18 u |
11 u |
528 |
|
- 4 u |
+ 4 u |
|
15 u |
14 u |
15 u |
528 |
Number of beads that Hilda must give to Eva
= 15 u - 11 u
= 4 u
= 4 x 12
= 48
Answer(s): 48