Penelope, Gem and Xylia have 126 stamps. Penelope has
34 as many stamps as Gem. Xylia's stamps is
15 of the total number of Penelope's and Gem's stamps. How many stamps must Gem give to Xylia so that both Penelope and Xylia will have the same number of stamps?
Penelope |
Gem |
Xylia |
Total |
5x7 = 35 u |
1x7 = 7 u |
|
3x5 = 15 u |
4x5 = 20 u |
|
|
15 u |
20 u |
7 u |
126 |
Total number of stamps
= 15 u + 20 u + 7 u
= 42 u
42 u = 126
1 u = 126 ÷ 42 = 3
Penelope |
Gem |
Xylia |
Total |
15 u |
20 u |
7 u |
126 |
|
- 8 u |
+ 8 u |
|
15 u |
12 u |
15 u |
126 |
Number of stamps that Gem must give to Xylia
= 15 u - 7 u
= 8 u
= 8 x 3
= 24
Answer(s): 24