Shannon, Vanessa and Joelle have 384 coins. Shannon has
35 as many coins as Vanessa. Joelle's coins is
15 of the total number of Shannon's and Vanessa's coins. How many coins must Vanessa give to Joelle so that both Shannon and Joelle will have the same number of coins?
| Shannon |
Vanessa |
Joelle |
Total |
5x8 =
40 u |
1x8 =
8 u |
|
3x5 =
15 u |
5x5 =
25 u |
|
|
| 15 u |
25 u |
8 u |
384 |
Total number of coins
= 15 u + 25 u + 8 u
= 48 u
48 u = 384
1 u = 384 ÷ 48 = 8
| Shannon |
Vanessa |
Joelle |
Total |
| 15 u |
25 u |
8 u |
384 |
| |
- 7 u |
+ 7 u |
|
| 15 u |
18 u |
15 u |
384 |
Number of coins that Vanessa must give to Joelle
= 15 u - 8 u
= 7 u
= 7 x 8
= 56
Answer(s): 56
