Opal, Kathy and Lynn have 270 cards. Opal has
45 as many cards as Kathy. Lynn's cards is
14 of the total number of Opal's and Kathy's cards. How many cards must Kathy give to Lynn so that both Opal and Lynn will have the same number of cards?
Opal |
Kathy |
Lynn |
Total |
4x9 = 36 u |
1x9 = 9 u |
|
4x4 = 16 u |
5x4 = 20 u |
|
|
16 u |
20 u |
9 u |
270 |
Total number of cards
= 16 u + 20 u + 9 u
= 45 u
45 u = 270
1 u = 270 ÷ 45 = 6
Opal |
Kathy |
Lynn |
Total |
16 u |
20 u |
9 u |
270 |
|
- 7 u |
+ 7 u |
|
16 u |
13 u |
16 u |
270 |
Number of cards that Kathy must give to Lynn
= 16 u - 9 u
= 7 u
= 7 x 6
= 42
Answer(s): 42