Three bags, S, T and U contained a certain number of coins. Bag U contained
16 as many coins as S and T combined. There were 70 more coins in Bag S than in Bag U. Bag T contained 170 more coins than Bag U. How many coins were in Bag T?
Bag S |
Bag T |
Bag U |
Total |
6 u |
1 u |
7 u |
1 u + 70 |
1 u + 170 |
|
|
The total number of coins in Bag S and Bag T is repeated.
1 u + 70 + 1 u + 170 = 6 u
2 u + 240 = 6 u
6 u - 2 u = 240
4 u = 240
1 u = 240 ÷ 4 = 60
Number of coins in Bag T
= 1 u + 170
= 1 x 60 + 170
= 230
Answer(s): 230