Three packets, N, P and Q contained a certain number of coins. Packet Q contained
15 as many coins as N and P combined. There were 62 more coins in Packet N than in Packet Q. Packet P contained 163 more coins than Packet Q. How many coins were in Packet P?
Packet N |
Packet P |
Packet Q |
Total |
5 u |
1 u |
6 u |
1 u + 62 |
1 u + 163 |
|
|
The total number of coins in Packet N and Packet P is repeated.
1 u + 62 + 1 u + 163 = 5 u
2 u + 225 = 5 u
5 u - 2 u = 225
3 u = 225
1 u = 225 ÷ 3 = 75
Number of coins in Packet P
= 1 u + 163
= 1 x 75 + 163
= 238
Answer(s): 238