Three packets, F, G and H contained a certain number of pens. Packet H contained
310 as many pens as F and G combined. There were 75 more pens in Packet F than in Packet H. Packet G contained 153 more pens than Packet H. How many pens were in Packet G?
Packet F |
Packet G |
Packet H |
Total |
10 u |
3 u |
13 u |
3 u + 75 |
3 u + 153 |
|
|
The total number of pens in Packet F and Packet G is repeated.
3 u + 75 + 3 u + 153 = 10 u
6 u + 228 = 10 u
10 u - 6 u = 228
4 u = 228
1 u = 228 ÷ 4 = 57
Number of pens in Packet G
= 3 u + 153
= 3 x 57 + 153
= 324
Answer(s): 324