Three packets, E, F and G contained a certain number of cards. Packet G contained
211 as many cards as E and F combined. There were 64 more cards in Packet E than in Packet G. Packet F contained 146 more cards than Packet G. How many cards were in Packet F?
Packet E |
Packet F |
Packet G |
Total |
11 u |
2 u |
13 u |
2 u + 64 |
2 u + 146 |
|
|
The total number of cards in Packet E and Packet F is repeated.
2 u + 64 + 2 u + 146 = 11 u
4 u + 210 = 11 u
11 u - 4 u = 210
7 u = 210
1 u = 210 ÷ 7 = 30
Number of cards in Packet F
= 2 u + 146
= 2 x 30 + 146
= 206
Answer(s): 206