Three packets, H, J and K contained a certain number of buttons. Packet K contained
17 as many buttons as H and J combined. There were 80 more buttons in Packet H than in Packet K. Packet J contained 190 more buttons than Packet K. How many buttons were in Packet J?
Packet H |
Packet J |
Packet K |
Total |
7 u |
1 u |
8 u |
1 u + 80 |
1 u + 190 |
|
|
The total number of buttons in Packet H and Packet J is repeated.
1 u + 80 + 1 u + 190 = 7 u
2 u + 270 = 7 u
7 u - 2 u = 270
5 u = 270
1 u = 270 ÷ 5 = 54
Number of buttons in Packet J
= 1 u + 190
= 1 x 54 + 190
= 244
Answer(s): 244