Three bags, P, Q and R contained a certain number of pencils. Bag R contained
314 as many pencils as P and Q combined. There were 58 more pencils in Bag P than in Bag R. Bag Q contained 142 more pencils than Bag R. How many pencils were in Bag Q?
Bag P |
Bag Q |
Bag R |
Total |
14 u |
3 u |
17 u |
3 u + 58 |
3 u + 142 |
|
|
The total number of pencils in Bag P and Bag Q is repeated.
3 u + 58 + 3 u + 142 = 14 u
6 u + 200 = 14 u
14 u - 6 u = 200
8 u = 200
1 u = 200 ÷ 8 = 25
Number of pencils in Bag Q
= 3 u + 142
= 3 x 25 + 142
= 217
Answer(s): 217